Namma Kalvi 12th Chemistry

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Namma Kalvi 12th Chemistry. We covered all the Namma Kalvi 12th Chemistry MCQs in this post for free so that you can practice well for the exam.

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    Namma Kalvi 12th Chemistry Objective for Students

    Diethyl ketone sodium bisulphite reacts with dilute acid or base to give:

    (A) Pentanal

    (B) Pentanone

    (C) Butanal

    (D) Butanone

    Option b – Pentanone

    The most acidic hydrogen atom in alkanals is located at the:

    (A) Delta position

    (B) Gamma position

    (C) Alpha position

    (D) Beta position

    Option c – Alpha position

    The detection of the oxo group in an organic compound can be done using:

    (A) Tetracarbonyl nickel

    (B) Sodium nitropruside

    (C) Sodium dicyano aurate

    (D) Lithium hydrido aluminate

    Option b – Sodium nitropruside

    The anion of propanone obtained by alkali reacts with nitropruside ion to give a red-colored complex, indicating the presence of:

    (A) Ester group

    (B) Formyl group

    (C) Ether group

    (D) Oxo group

    Option d – Oxo group

    The anion of a ketone formed by alkali reacts with nitropruside ion to give a:

    (A) Black-colored complex

    (B) Violet-colored complex

    (C) Red-colored complex

    (D) Blue-colored complex

    Option c – Red-colored complex

    The least reactive compound towards hydrogen cyanide is:

    (A) Ethyl methyl ketone

    (B) Dimethyl ketone

    (C) Ethanal

    (D) Methanal

    Option a – Ethyl methyl ketone

    Mendelonitrile is prepared from:

    (A) Ethanal and hydrazine

    (B) Ethanal and formonitrile

    (C) Propanone and ammonia

    (D) Benzene carbaldehyde and formonitrile

    Option d – Benzene carbaldehyde and formonitrile

    Cyanohydrin formation is a “step-up” reaction as a new:

    (A) Carbon-Nitrogen single bond is formed.

    (B) Carbon-Oxygen single bond is formed.

    (C) Carbon-Carbon single bond is formed.

    (D) Carbon-Sulphur single bond is formed.

    Option c – Carbon-Carbon single bond is formed

    Propanone reacts with formonitrile to give:

    (A) Dimethyl ketone cyanohydrin

    (B) Ethanal cyanohydrin

    (C) Propanal cyanohydrin

    (D) Propane nitrile

    Option a – Dimethyl ketone cyanohydrin

    During the reaction between ethanal and ammonical silver nitrate, the oxidation state of silver changes from:

    (A) +3 to zero

    (B) +2 to +3

    (C) +1 to zero

    (D) +1 to +2

    Option c – +1 to zero

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