Number System MCQ

41 If 603 x 28 = 63 x 4 x ......, then the number in the blank space is 1. 67 2. 21 3. 28 4. 63

40 If 30028 = 28 Ones + 28 Thousand + ....... Tens, then the number in the blank space is ( Number System MCQ ) 1. 280 2. 28 3. 128 4. 200

39 The difference between the place value of 5 in 29503 and the face value of 7 in 32071 is 1. 493 2. 2 3. 43 4. 430

38 If the difference of remainders obtained on dividing 26679 by 39 and 29405 by 34, is divided by 18, then the remainder will be 1. 8 2. 9 3. 3 4. 5

37 If 1001 x 111 = 110000 + 11 x ....., then the number in, the blank space is 1. 121 2. 101 3. 211 4. 111

36 If 112 ones + 12 thousand = 11012 + ..... tens, then the number in the blank space is ( Number System MCQ ) 1. 111 2. 112 3. 101 4. 110

35 If (the place value of 5 in 15201) + (the place value of 6 in 2659) =7 x ......, then the number in the blank space is 1. 90 2. 900 3. 80 4. 800

33 The sum of remainders obtained by dividing 12112 by 11 and 13223 by 13 is 1. 3 2. 4 3. 5 4. 2

32 10 thousand + 10 hundred + 10 tens equals to 1. 11110 2. 11100 3. 11010 4. 101010

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Number System MCQ

43 When the remainder obtained on dividing 80808 by 108 is divided by the remainder obtained on dividing 90909 by 109, then the quotient is 1. 12 2. 3 3. 6 4. 8

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41 If 603 x 28 = 63 x 4 x ......, then the number in the blank space is 1. 67 2. 21 3. 28 4. 63

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40 If 30028 = 28 Ones + 28 Thousand + ....... Tens, then the number in the blank space is ( Number System MCQ ) 1. 280 2. 28 3. 128 4. 200

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39 The difference between the place value of 5 in 29503 and the face value of 7 in 32071 is 1. 493 2. 2 3. 43 4. 430

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38 If the difference of remainders obtained on dividing 26679 by 39 and 29405 by 34, is divided by 18, then the remainder will be 1. 8 2. 9 3. 3 4. 5

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37 If 1001 x 111 = 110000 + 11 x ....., then the number in, the blank space is 1. 121 2. 101 3. 211 4. 111

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36 If 112 ones + 12 thousand = 11012 + ..... tens, then the number in the blank space is ( Number System MCQ ) 1. 111 2. 112 3. 101 4. 110

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35 If (the place value of 5 in 15201) + (the place value of 6 in 2659) =7 x ......, then the number in the blank space is 1. 90 2. 900 3. 80 4. 800

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33 The sum of remainders obtained by dividing 12112 by 11 and 13223 by 13 is 1. 3 2. 4 3. 5 4. 2

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32 10 thousand + 10 hundred + 10 tens equals to 1. 11110 2. 11100 3. 11010 4. 101010

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