Balaji Publication Chemistry Class 11. We covered all the Balaji Publication Chemistry Class 11 in this post for free so that you can practice well for the exam.
Install our MCQTUBE Android app from the Google Play Store and prepare for any competitive government exams for free.
These types of competitive MCQs appear in the exams like MHT-CET, NEET, JEE (Mains), and other Competitive Examinations, etc. We created all the competitive exam MCQs into several small posts on our website for your convenience.
You will get their respective links in the related posts section provided below.
Related Posts:
- Chemistry Lesson Plan in Hindi
- Pharmaceutical Chemistry 2 Model Answer Paper
- HSST Chemistry Previous Question Papers
Balaji Publication Chemistry Class 11 Objective for Students
The vapour pressure of water at 298 K is 23.75 mmHg. The relative lowering in vapour pressure of 5% aqueous urea solution at the same temperature is
(A) 0.016
(B) 0.16
(C) 23.37
(D) 27.23
Option a – 0.016
An aqueous solution containing 28% by mass of liquid A with a molar mass of 140 has a vapour pressure of 160 mmHg at 30°C. The vapour pressure of pure liquid A is (vapour pressure of water at 30°C = 150 mmHg)
(A) 360
(B) 10
(C) 180
(D) 400
Option a – 360
The boiling point is the temperature of the liquid at which the vapour pressure of the liquid is equal to
(A) Critical pressure
(B) Atmospheric pressure
(C) Normal pressure
(D) the Vapour pressure of its solid
Option b – Atmospheric pressure
When a solid substance is dissolved in a solvent then
(A) the Boiling point of the liquid is depressed.
(B) No effect on boiling point.
(C) The boiling point of the liquid is elevated.
(D) Change depends on the polarity of the solution.
Option c – The boiling point of the liquid is elevated
The vapour pressure of benzene at a certain temperature is 640 mmHg. 2.175 g of nonvolatile solute was added into 39.08 g of benzene. The vapour pressure of the solution becomes 600 mmHg. The molar mass of the solute is
(A) 49.50
(B) 69.60
(C) 59.60
(D) 79.82
Option b – 69.60
The vapour pressure of two liquids A and B are 80 atm and 60 atm respectively. The total vapour pressure of the solution obtained by mixing 3 moles of A and 2 moles of B would be
(A) 72 atm
(B) 20 atm
(C) 68 atm
(D) 140 atm
Option a – 72 atm
The vapour pressure of benzene at 30°C is 121.8 mm. 15 g of non-volatile solute is dissolved in 250 g of benzene, and the vapour pressure of the solution becomes 120.2 mm. The molecular mass of the solute is
(A) 35.67 g
(B) 356.7 g
(C) 432.8 g
(D) 502.7 g
Option b – 356.7 g
The lowering in vapour pressure of the solvent occurs when
(A) Solute is volatile
(B) Solute is non-volatile
(C) Solute is non-electrolyte
(D) All of these
Option d – All of these
The vapour pressure of pure water at room temperature is 40 mm. In an aqueous solution of a nonvolatile solute, the mole fraction of water is 0.9. The vapour pressure of the solution will be
(A) 44.4 mm Hg
(B) 40 mm Hg
(C) 40.4 mm Hg
(D) 36 mm Hg
Option d – 36 mm Hg
Two liquids A and B in a solution. The vapour pressure of pure A liquid is 70 mm at 300 K. If the Mole fraction of B is 0.2 and the total vapour pressure of the solution is 84 mm. The vapour pressure of B is
(A) 140 mm Hg
(B) 56 mm Hg
(C) 70 mm Hg
(D) 14 mm Hg
Option a – 140 mm Hg
The solution which obeys Raoult’s law at all? concentration and all temperature is
(A) Real solution
(B) Dilute solution
(C) Binary solution
(D) Ideal solution
Option d – Ideal solution
We covered all the balaji publication chemistry class 11 above in this post for free so that you can practice well for the exam.
Check out the latest MCQ content by visiting our mcqtube website homepage.
Also, check out:
