Chapter Wise Test Series for NEET. We covered all the Chapter Wise Test Series for NEET Students in this post for free so that you can practice well for the exam.
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MCQ on Biomolecules for NEET Students
Assertion: Propan-1-ol is less soluble in water than methanol. Reason: With the increase in the size of the alkyl group, the solubility of the alcohols decreases.
(A) Assertion and Reason are true. The reason is the correct explanation of the Assertion.
(B) Assertion and Reason are true. The reason is not the correct explanation of the Assertion.
(C) The assertion is true, and the Reason is false.
(D) The assertion is false, Reason is true.
Option a – Assertion and Reason are true. The reason is the correct explanation of the Assertion.
Which of the following properties/characteristics are different for the compounds (+) 2-butanol and (-) 2-butanol? (I) Solubility in water (II) Specific rotation (III) Spatial arrangement around the chirality center (IV) Angle around the chirality center (V) Refractive index (VI) Reaction with sodium metal
(A) I, II, VI
(B) II, III
(C) III, IV, V
(D) I, III, IV
Option b – II, III
The common name of 1-bromo-2-methylpropane is ……..
(A) tert-butyl bromide
(B) sec-butyl bromide
(C) isobutyl bromide
(D) n-butyl bromide
Option c – isobutyl bromide
Which of the following conversion (single step) can be carried out by Swarts reaction?
(A) Chloroethane → Fluoroethane
(B) Chloroethane → Iodoethane
(C) Ethanol → Chloroethane
(D) Ehanol → Bromoethane
Option a – Chloroethane → Fluoroethane
On heating phenyl methyl ether with HI, ……… are formed.
(A) iodobenzene and iodomethane
(B) phenol and iodomethane
(C) benzene and methanol
(D) phenol and methanol
Option b – phenol and iodomethane
……….. CANNOT be used as a starting material for the preparation of iodoform by using iodine and sodium hydroxide.
(A) Ethyl methyl ketone
(B) Isopropyl alcohol
(C) Acetaldehyde
(D) Isobutyl alcohol
Option d – Isobutyl alcohol
Sodium benzene sulphonate fused with sodium hydroxide forms ………. on acidic hydrolysis.
(A) benzene sulphonic acid
(B) benzoic acid
(C) phenol
(D) pyrogallol
Option c – phenol
Choose the CORRECT statement(s) from the following : (I) The C-X bond length is longer in chloromethane as compared to bromomethane. (II) The C-X bond length is longer in bromobenzene as compared to bromomethane. (III) The C-X bond length is longer in chloromethane as compared to chlorobenzene.
(A) Only (I)
(B) Only (III)
(C) (I) and (II)
(D) (II) and (III)
Option b – Only (III)
When propyne is treated with aqueous H₂SO4 in the presence of HgSO4, the product obtained is ………
(A) CH3 -CH2 – CHO
(B) CH3-CH2 – CO – CH3
(C) CH3 – CO – CH3
(D) CH3 – CH₂ – CH₂ – OH
Option c – CH3 – CO – CH3
One mole of compound ‘X’ on catalytic hydrogenation gives two moles of primary alcohol (Y). Identify ‘X’.
(A) Propanone
(B) Ethyl propanoate
(C) Propanal
(D) Propyl propanoate
Option d – Propyl propanoate
Aldehydes or ketones when treated with C6H5 – NH – NH₂, the product formed is ……….
(A) semicarbazone
(B) phenylhydrazone
(C) hydrazone
(D) oxime
Option b – phenylhydrazone
The conversion shown below can be carried out by using which of the following reagents? CH3CH₂CH=CH₂ -> CH3CH₂CH₂CH₂OH
(A) Conc. H₂SO4 and then heating with H₂0
(B) BH3/THF and then H₂O2, NaOH
(C) Alcoholic NaOH
(D) Moist Ag₂O
Option b – BH3/THF and then H₂O2, NaOH
Assertion p-Aminophenol is less acidic than phenol. Reason: Electron-donating groups do not favor the formation of phenoxide ions.
(A) Assertion and Reason are true. The reason is the correct explanation of the Assertion.
(B) Assertion and Reason are true. The reason is not the correct explanation of the Assertion.
(C) The assertion is true. The reason is false.
(D) The assertion is false. The reason is true.
Option a – Assertion and Reason are true. The reason is the correct explanation of the Assertion.
When phenol is heated with a nitrating mixture, it forms a compound (X). Which of the following group is NOT present in compound (X)? (I)-CHO (II) -NO₂ (III) -COOH (IV)−NH, (V) -OH
(A) (I) and (II)
(B) (I) and (IV)
(C) (II), (III) and (IV)
(D) (I), (III), and (IV)
Option d – (I), (III), and (IV)
Compound (X) undergoes alkaline hydrolysis by SN1 route to form ‘Y’ and ‘Z’ in equal proportion. ‘Y’ and ‘Z’ are enantiomers and the final reaction mixture is racemic. Identify compound (X).
(A) 2-Bromo-2-methylpropane
(B) 1-Bromo-1-phenylethane
(C) 2-Bromopropane
(D) 1-Bromo-2-phenylpropane
Option b – 1-Bromo-1-phenylethane
Which of the following is allylic alcohol? ( Chapter Wise Test Series for NEET )
(A) 2-Phenylpropan-2-ol
(B) 2-Methylpropan-2-ol
(C) Prop-1-en-1-ol
(D) 2-Methylbut-3-en-2-ol
Option d – 2-Methylbut-3-en-2-ol
In which of the following molecules, all the carbon atoms are sp² hybridized?
(A) Acetaldehyde
(B) Acrolein
(C) Glyceraldehyde
(D) Crotonaldehyde
Option b – Acrolein
When an organic compound (X) is treated with carbon monoxide and HCl under high pressure in the presence of a catalyst (Anhy. AlCl3 + Cu₂Cl₂), another organic compound (Y) is obtained. Compound (Y) is heated with alkaline KMnO4 to obtain benzoic acid. Compound (Y) gives a positive result with Schiff reagent but a negative result with Fehling solution. Identify (X) and (Y) respectively.
(A) X= Benzene; Y = Benzophenone
(B) X = Toluene; Y = Benzaldehyde
(C) X = Benzene; Y = Benzaldehyde
(D) X = Benzene; Y = Acetophenone
Option c – X = Benzene; Y = Benzaldehyde
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