Centrifugal Force in Hindi for Students

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Centrifugal Force in Hindi. We covered all the Centrifugal Force in Hindi in this post for free so that you can practice well for the exam.

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Mock Test on Centrifugal Force for Students

A rod of length L is pivoted at one end and rotated in the horizontal plane with uniform angular velocity. If T₁ and T₂ are the tensions at points L/4 and 3L/4 away from pivoted ends

A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. Its kinetic energy is

A coin placed on a rotating table just slips when placed at a distance of 20 cm from the center. If the angular velocity of the table is doubled, then the distance of the coin at which it just begins to slip is :

An airplane moves with 64 m/s in a vertical loop of radius 120 m, force of the plane's seat on a 72 kg pilot while passing through the bottom part of the loop. (g= 10 m/s²) :

The horizontal velocity with which the body should be thrown so that it may move parallel to the surface of the earth along the equator is equal to

The bulging of the earth at the equator and flattening at the poles is due to :

A coin placed on a rotating table just slips when placed at a distance 4r from the center. On doubling the angular velocity of the table. The coin will just slip when the distance from the center is equal to

Mock Test on Centrifugal Force for Students

A rod of length L is pivoted at one end and rotated in the horizontal plane with uniform angular velocity. If T₁ and T₂ are the tensions at points L/4 and 3L/4 away from pivoted ends

(A) T₁>T₂

(B) T₂>T₁

(D) Relation between T₁ and T₂ depends on the sense of rotation.

Option b - T₂>T₁

A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. Its kinetic energy is

(A) 0.1 J

(B) 0.2 J

(D) 1.0 J

Option d - 1.0 J

A coin placed on a rotating table just slips when placed at a distance of 20 cm from the center. If the angular velocity of the table is doubled, then the distance of the coin at which it just begins to slip is :

(A) 20 cm

(B) 10 cm

(D) 4 cm

Option c - 5 cm

An airplane moves with 64 m/s in a vertical loop of radius 120 m, force of the plane's seat on a 72 kg pilot while passing through the bottom part of the loop. (g= 10 m/s²) :

(A) 720 N

(B) 1737.6 N

(D) 3177.6 N

Option d - 3177.6 N

The horizontal velocity with which the body should be thrown so that it may move parallel to the surface of the earth along the equator is equal to

(A) 8 km/s

(B) 11.2 km/s

(D) 20 km/s

Option a - 8 km/s

The bulging of the earth at the equator and flattening at the poles is due to :

(A) centripetal force

(B) gravitational force

(D) electrostatic force

Option c - centrifugal force

A coin placed on a rotating table just slips when placed at a distance 4r from the center. On doubling the angular velocity of the table. The coin will just slip when the distance from the center is equal to

(A) 4r

(B) 2r

(D) r/4

Option c - r

We covered all the centrifugal force in Hindi above in this post for free so that you can practice well for the exam.

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Mock Test on Centrifugal Force for Students

A rod of length L is pivoted at one end and rotated in the horizontal plane with uniform angular velocity. If T₁ and T₂ are the tensions at points L/4 and 3L/4 away from pivoted ends

A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. Its kinetic energy is

A coin placed on a rotating table just slips when placed at a distance of 20 cm from the center. If the angular velocity of the table is doubled, then the distance of the coin at which it just begins to slip is :

An airplane moves with 64 m/s in a vertical loop of radius 120 m, force of the plane's seat on a 72 kg pilot while passing through the bottom part of the loop. (g= 10 m/s²) :

The horizontal velocity with which the body should be thrown so that it may move parallel to the surface of the earth along the equator is equal to

The bulging of the earth at the equator and flattening at the poles is due to :

A coin placed on a rotating table just slips when placed at a distance 4r from the center. On doubling the angular velocity of the table. The coin will just slip when the distance from the center is equal to

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