ISC Class 12 Physics Chapter Wise Questions with Solutions

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ISC Class 12 Physics Chapter Wise Questions with Solutions. We covered all the ISC Class 12 Physics Chapter Wise Important Questions with Solutions pdf file provided in this post for free so that you can practice well for the exam.

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ISC Class 12 Physics Mock Test for Students

Which of the following phenomena is not explained by Huygens’s construction of wavefront?

(A) Refraction

(B) Reflection

(C) Diffraction

(D) Origin of spectra

Option d – Origin of spectra

The lines drawn normally to the wavefront represent a path of light known as

(A) plane waves

(B) rays

(C) spherical waves

(D) all of these

Option b – rays

The angle of reflection is the angle between :

(A) reflected wavefront and normal to reflecting surface

(B) reflecting surface and normal to reflecting surface

(C) reflected ray and reflecting surface

(D) reflected wavefront and reflecting surface

Option d – reflected wavefront and reflecting surface

When light is reflected from the mirror :

(A) its wavelength changes

(B) its speed changes

(C) its phase changes

(D) its frequency changes

Option c – its phase changes

If the angle of incidence and angle of refraction is the same, then the ratio of the size of the incident and refracted wavefront is :

(A) 2 : 1

(B) 1 : 2

(C) 1 : 1

(D) 1 : 3

Option c – 1 : 1

As the plane wavefront propagates, its radius of curvature :

(A) decreases

(B) increases

(C) first increases and then decreases

(D) remains infinite

Option d – remains infinite

A wave can transmit ……. from one place to another :

(A) energy

(B) amplitude

(C) wavelength

(D) matter

Option a – energy

Huygen’s concept of secondary waves (source) is :

(A) used to determine the wavelength of light

(B) used to determine the speed of light

(C) a geometrical method to find the position of a new wavefront

(D) all of these

Option c – a geometrical method to find the position of a new wavefront

Huygens principle postulates :

(A) the wave is a transverse one

(B) each point on the wavefront is in a different phase

(C) the tangent to the wavefront is the direction of propagation of the wave

(D) each point on the wavefront is the center of a new disturbance

Option d – each point on the wavefront is the center of a new disturbance

Light from the sun will be reaching on Earth’s surface in the form of :

(A) plane wavefront

(B) spherical wavefront

(C) cylindrical wavefront

(D) elliptical wavefront

Option a – plane wavefront

Cylindrical wavefront is obtained from a :

(A) the vertical linear source

(B) the horizontal linear source

(C) inclined linear source

(D) all of the above

Option d – all of the above

A narrow slit is placed in front of a source of light, and the wavefront originating from the narrow slit is :

(A) plane wavefront

(B) cylindrical wavefront

(C) spherical wavefront

(D) all of these

Option b – cylindrical wavefront

A perpendicular drawn at any point on the wavefront in the direction of propagation of light is :

(A) wave normal

(B) wavelength

(C) arc of circle

(D) wavefront

Option a – wave normal

Wavefront and a ray of light are :

(A) perpendicular to each other

(B) parallel to each other

(C) converges from each other

(D) diverge from each other

Option a – perpendicular to each other

The wave normals drawn on spherical and plane wavefronts respectively are :

(A) diverges and parallel

(B) parallel and diverges

(C) converges and diverges

(D) converges and parallel

Option a – diverges and parallel

The wavefront originating from the point source of light at a finite distance gives rise to

(A) plane wavefront

(B) cylindrical wavefront

(C) spherical wavefront

(D) elliptical wavefront

Option c – spherical wavefront

A small part of a spherical wavefront from a point source of light at an infinite distance gives rise to

(A) plane wavefront

(B) spherical wavefront

(C) cylindrical wavefront

(D) elliptical wavefront

Option a – plane wavefront

A point source of light is at the focus of the convex lens. The outcoming light through the lens will be in the form of :

(A) plane wavefront

(B) spherical wavefront

(C) cylindrical wavefront

(D) elliptical wavefront

Option a – plane wavefront

D.C ammeter is connected in a circuit through which A.C of 50 Hz flows. The ammeter would read :

(A) Peak value of current

(B) Average current

(C) Zero

(D) RMS value of current

Option c – Zero

An ammeter should have very low resistance, so that it may :

(A) Not burnout

(B) Have better stability

(C) Show large deflection.

(D) Not change the value of current

Option d – Not change the value of current

An ammeter has a resistance of G Ω and a range of I ampere. The value of the resistance used in parallel to convert it into an ammeter of range nl amperes is :

(A) n G

(B) G/n

(C) (n-1) G

(D) G/(n-1)

Option d – G/(n-1)

If the galvanometer current is 10 mA, the resistance of the galvanometer is 40 Ω and the shunt of 2 Ω is connected to the galvanometer, the maximum current which can be measured by the ammeter is

(A) 0.21 A

(B) 210 A

(C) 2.1 A

(D) 21 A

Option a – 0.21 A

An ammeter has a resistance of 100 Ω. A potential difference of 50 mV between its terminals gives full-scale deflection. How will you convert it into an ammeter of range 5A? :

(A) 0.01 Ω In parallel

(B) 0.1 Ω In parallel

(C) 1 Ω In parallel

(D) 10 Ω In parallel

Option a – 0.01 Ω In parallel

In an ammeter, 5% of the main current is passing through the galvanometer. If the resistance of the galvanometer is G then the resistance of the shunt will be :

(A) G/19

(B) G/5

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(C) 5G

(D) 19G

Option a – G/19

To send 10 % of the main current through a moving coil galvanometer of resistance 99 Ω, the shunt required is :

(A) 9.9 Ω

(Β) 10 Ω

(C) 11 Ω

(D) 9 Ω

Option c – 11 Ω

This question has statement I and statement II. Of the four choices given after the statements, choose the one that best describes the two statements. Statement – I: Higher the range, the greater the resistance of the ammeter. Statement II: To increase the range of the ammeter, an additional shunt needs to be used across it.

(A) Statement- I is true, Statement – II is true, Statement – II is the correct explanation of Statement I

(B) Statement- I is true, Statement – II is true, Statement II is not the correct explanation of Statement – I.

(C) Statement – I is true, and Statement – II is false.

(D) Statement – I is false, and Statement – II is true.

Option c – Statement – I is true, and Statement – II is false

When an ammeter is connected in series the resistance of the circuit is :

(A) Increased

(B) Decreased

(C) Unchanged

(D) Sometimes increases

Option b – Decreased

The resistance of an ideal Ammeter is :

(A) Zero

(B) Low

(C) High

(D) Infinite

Option a – Zero

The parallel combination of galvanometer and shunt is called :

(A) Voltmeter

(B) Ohmmeter

(C) Ammeter

(D) Speedometer

Option c – Ammeter

The range of the ammeter can be increased by :

(A) Decreasing the shunt

(B) Increasing the shunt

(C) Changing the scale

(D) Removing the shunt.

Option a – Decreasing the shunt

The resistance of an ammeter in the 1-ampere range is 0.018 Ω. How will you convert it to an ammeter measuring upto 10 A :

(A) 1Ω In parallel

(B) 0.02 Ω In parallel

(C) 0.002 Ω In parallel

(D) 0.001 Ω In parallel

Option c – 0.002 Ω In parallel

Voltmeter reading up to 150 volts can be converted into an ammeter of 8 A range, having a resistance of 300 Ω is :

(A) 20Ω in series

(B) 20Ω in parallel

(C) 10Ω in series

(D) 10Ω in parallel

Option b – 20Ω in parallel

An ammeter consists of a galvanometer of resistance 50 Ω and an external resistance of 5 Ω. The resistance of the ammeter is :

(A) 5 Ω

(Β) 45 Ω

(C) 4.5 Ω

(D) 55 Ω

Option c – 4.5 Ω

A battery of emf 1.4 V and internal resistance of 2 ohms is connected to a resistor of 100 ohms, through an ammeter. The resistance of the ammeter is 4/3 ohm. A voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. The resistance of the voltmeter is :

(Α) 400 Ω

(Β) 300 Ω

(C) 200 Ω

(D) 100 Ω

Option c – 200 Ω

A thick wire is stretched so that its length becomes three times. Assuming that there is no change in density, what is the ratio of the change in the resistance of the wire to the initial resistance of the wire?

(A) 2 : 1

(B) 4 : 1

(C) 3 : 1

(D) 1 : 4

Option c – 3 : 1

Kirchhoff’s second law is based on the law of conservation of

(A) Charge

(B) Energy

(C) Momentum

(D) Current

Option b – Energy

According to Kirchhoff’s law, the algebraic sum of the product of current and resistance as well as emf in a closed loop is :

(A) Zero

(B) Greater than zero

(C) Less than zero

(D) Depends upon emf in a closed loop

Option a – Zero

Kirchhoff’s junction law is equivalent to

(A) conservation of energy

(B) conservation of charge

(C) conservation of electric potential

(D) conservation of electric flux

Option b – conservation of charge

Two resistance wires joining in parallel have a resultant resistance of (6/5)Ω. One of the wires breaks. The effective resistance is 222. The resistance of the broken wire was :

(A) 6/5Ω

(Β) 3Ω

(C) 3/5Ω

(D) zero

Option b – 3Ω

A cell supplies a current of 0.9 A through a 2Ω resistor and a current of 0.3 A through a 7Ω resistor. The internal resistance of the cell is :

(A) 0.5Ω

(B) 1Ω

(C) 2Ω

(D) 4Ω

Option a – 0.5Ω

Ohm law is the relation between :

(A) I = VR

(B) I = V/R

(C) I = V-R

(D) I = V+R

Option b – I = V/R

A galvanometer of resistance 98 Ω is shunted by resistance 2 Ω. The fraction of current through the galvanometer is :

(A) 1/50

(B) 1/49

(C) 1/2

(D) 1/98

Option a – 1/50

In parallel arrangement if (R₁>R₂). The power dissipated in resistance R₁ will be :

(A) more than R₂

(B) less than R₂

(C) equal to R₂

(D) depending on the internal resistance of the cell

Option b – less than R₂

A student is given several metal sheets each of area A. Two such plates when placed one over the other with a paper sheet in between have capacity C. How many plates will the student require to have an assembly of capacity 15 C?

(A) 10

(B) 15

(C) 16

(D) 17

Option c – 16

Two condensers of capacity 1 μF and 2 μF are connected in series and the system is charged to 120 V. The P. D. on 1 µF capacitor will be :

(A) 40 V

(B) 60 V

(C) 80 V

(D) 120 V

Option c – 80 V

A parallel plate capacitor is made by stacking n equally spaced plates connected alternately. If the capacitance between any two plates is C. Then the resulting capacitance is :

(A) n C

(B) (n + 1) C

(C) (n-1) C

(D) C/ n

Option c – (n-1) C

Three capacitors of equal capacities are to be connected in different ways to give different capacities, the number of ways in which they can be connected are :

(A) two

(B) three

(C) four

(D) any number

Option c – four

A 500 μF capacitor is charged at a steady rate of 100 μC per second. The potential across the capacitor will be 10 V after an interval of :

(A) 20 s

(B) 30 s

(C) 50 s

(D) 25 s

Option c – 50 s

If a capacitor of 60 µF has a charge of 30 mC on each plate, then the energy stored is :

(A) 1.5 J

(B) 5 J

(C) 7 J

(D) 7.5 J

Option d – 7.5 J

Two capacitors of equal capacities when connected in series, they have some resultant capacity. Now individual condensers are connected in parallel, their resultant capacity is :

(A) the same as the previous value

(B) two times the previous value

(C) three times the previous value

(D) four times the previous value

Option d – four times the previous value

The distance between the plates of a parallel plate air condenser is 2 mm and P.D. is 200 V. The energy density in the space between the plates is :

(A) 4.425 J/m³

(B) 0.04425 J/m³

(C) 8.85 J/m³

(D) 0.885 J/m³

Option b – 0.04425 J/m³

A condenser is charged through a potential difference of 200 V and possesses a charge of 0.1 coulombs. When discharged it would release the energy of

(A) 1 J

(B) 5 J

(C) 10 J

(D) 20 J

Option c – 10 J

A 4 μF capacitor is charged to 400 V. If its plates are joined through a resistance of 2 KQ, then heat produced in the resistance is :

(A) 0.64 J

(B) 1.28 J

(C) 0.32 J

(D) 0.16 J

Option c – 0.32 J

In a charged condenser, the energy resides in

(A) the positively charged plate

(B) the negatively charged plate

(C) the field between the plates

(D) both (A) and (B)

Option c – the field between the plates

A capacitor C has charge Q and the stored energy is W. If the charge is increased to 2 Q. The stored energy will be :

(A) W

(B) 2 W

(C) 4 W

(D) 3 W

Option c – 4 W

The work done in taking a unit positive charge once around a charge +q (stationary) along a circle of radius r is :

(A) positive

(B) negative

(C) zero

(D) infinite

Option c – zero

A parallel plate condenser has a capacitance of 50 μF in air and 110 uF when immersed in oil. The dielectric constant k of the oil is :

(A) 11

(B) 5

(C) 2.2

(D) 2.5

Option c – 2.2

A parallel plate capacitor has a capacity of C. If the separation between the plates is doubled and the dielectric medium is inserted between the plates, the capacity becomes 3 C. The dielectric the new constant of the medium is :

(A) 3

(B) 6

(C) 1.5

(D) 2

Option b – 6

In a parallel plate condenser, the radius of each circular plate is 12 cm and the distance between the plates is 5 mm. There is a glass slab of 3 mm thick and a dielectric constant of 6. The capacity of the condenser will be :

(A) 140 pF

(B) 56 pF

(C) 160 pF

(D) 1.6 pF

Option c – 160 pF

A parallel plate condenser is immersed in an oil of dielectric constant 3. The field between the plate is

(A) increases and proportional to 3

(B) increases and proportional to 1/3

(C) decreases and is proportional to 1/3

(D) decreases and is proportional to 1/4

Option c – decreases and is proportional to 1/3

A dielectric is introduced between the elements of the condenser kept at the constant potential difference. Then the charge on the condenser :

(A) increases

(B) decreases

(C) remains the same

(D) first increases and then decreases

Option a – increases

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