First Law of Thermodynamics in Hindi. We covered all the First Law of Thermodynamics in Hindi in this post for free so that you can practice well for the exam.
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Mock Test on First Law of Thermodynamics for Students
A system is given 300 cal of heat and it does 600J of work. How much does the internal energy of the system change in this process? (J = 4.18 J/cal)
(A) -528.2 J
(B) -300 J
(C) 156.5 J
(D) 654 J
Option d - 654 J
The first law of thermodynamics is based on :
(A) Mass conservation
(B) Momentum conservation
(C) Energy conservation
(D) Heat exchange
Option c - Energy conservation
The pressure of a given mass of a gas in a thermodynamic system is changed in such a way that 20 J of heat is released from the gas and 8J of work is done on the gas. If the initial internal energy of the gas was 30 J then the final internal energy will be :
(A) 2 J
(B) 18 J
(C) 42 J
(D) 50 J
Option b - 18 J
If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J, then the amount of external work done is :
(A) 150 J
(B) 110 J
(C) 70 J
(D) 40 J
Option c - 70 J
110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is :
(A) 40 J
(B) 70 J
(C) 110 J
(D) 150 J
Option b - 70 J
When the amount of work done is 300 cal and the change in internal energy is 167 cal, then the heat supplied is :
(A) 166 cal
(B) 333 cal
(C) 500 cal
(D) 400 cal
Option c - 500 cal
The first law of thermodynamics is given by :
(A) dQ = dU + PdV
(B) dQ = (dU + dV) P
(C) dQ = dU x PdV
(D) dQ = PdU + dv
Option a - dQ = dU + PdV
The first law of thermodynamics is concerned with the conservation of
(A) Mass
(B) Energy
(C) Momentum.
(D) Temperature
Option b - Energy
We consider a thermodynamic system. If du represents the increase in its internal energy and dW the work done by the system. Which of the following statement is true? :
(A) dU = -dW in an isothermal process
(B) dU = dW in an isothermal process
(C) dU = -dW in an adiabatic process
(D) dU = dW in an adiabatic process
Option c - dU = -dW in an adiabatic process
A gas expands from a volume of 2 m³ to 6 m³ at a constant pressure of 10 N/m² and then at the constant volume of 6 m³, the pressure is changed from 10 N/m² to 20 N/m². The work done by the gas is :
(A) 40 erg
(B) 40 J
(C) 60 J
(D) 100 J
Option b - 40 J
In an isothermal change of an ideal gas, dU = 0. The change in heat energy dQ is equal to :
(A) 0.5 dW
(B) dW
(C) 1.5 dW
(D) 2dW
Option b - dW
We covered all the first law of thermodynamics in Hindi above in this post for free so that you can practice well for the exam.
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