HNSB Physics. We covered all the HNSB Physics in this post for free so that you can practice well for the exam.
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HNSB Physics Mock Test for Students
The quantity which does not vary periodically in SHM is :
(A) Displacement
(B) Acceleration
(C) Total energy
(D) Velocity
Option c – Total energy
A particle of mass m is hanging vertically by an ideal spring of force constant k, If the mass is made to oscillate vertically, its total energy is :
(A) Maximum at the extreme position
(B) Maximum at the mean position
(C) Minimum at the mean position
(D) Same at all the position
Option d – Same at all the position
A particle in SHM oscillates with a frequency of then its kinetic energy varies as
(A) 2f
(B) f
(C) f/2
(D) 4f
Option a – 2f
A particle executes a simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy?
(A) 0.51 A
(B) 0.61 A
(C) 0.71 A
(D) 0.81 A
Option c – 0.71 A
Two springs of force constant k and 2k are stretched by the same force. If W₁ and W₂ are the energies stored in them respectively then :
(A) W₁=W₂
(B) W₁ = 2W₂
(C) W₁=1/2 W₂
(D) W=1/4 W₂
Option b – W₁ = 2W₂
A simple pendulum has a length of 1 m and energy equal to 0.2 joules when its amplitude is 4 cm. Its energy when the length is doubled is :
(A) 0.04 J
(B) 0.02 J
(C) 0.1 J
(D) 0.8 J
Option c – 0.1 J
The kinetic energy of a particle in SHM is equal to its potential energy when its displacement is :
(A) 50% of a
(B) 60% of a
(C) 70% of a
(D) 25% of a
Option c – 70% of a
The total energy of a particle in SHM is 4 J and the amplitude of SHM is 0.1 m:
(A) Maximum P.E. is 3 J
(B) Maximum K.E. is 3 J
(C) Maximum K.E. is 1 J
(D) Maximum P.E. and K.E. is 4 J
Option d – Maximum P.E. and K.E. is 4 J
A particle of mass 0.5 kg executes SHM. Its period of oscillation is 3.14 s and its total energy is 0.04 J its amplitude is :
(A) 40 cm
(B) 20 cm
(C) 10 cm
(D) 15 cm
Option b – 20 cm
When the displacement of a particle in SHM is one-third of the amplitude, what fraction of T.E. is P.E.:
(A) 1/2
(B) 1/9
(C) 1/4
(D) 4/3
Option b – 1/9
When the displacement of a particle in SHM is half of the amplitude then the ratio of its P.E. to K.E. is :
(A) 1/2
(B) 1
(C) 1/3
(D) 3
Option c – 1/3
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