Kinematics MCQ for NEET. We covered all the Kinematics MCQ for NEET in this post for free so that you can practice well for the exam.
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MCQ on Kinematics for NEET Students
Compared to a CE amplifier, the CB amplifier has
(A) lower input resistance.
(B) higher output resistance.
(C) lower current amplification.
(D) higher current amplification.
Option c – lower current amplification.
If the absorption transitions between the first and the fourth energy states of the hydrogen atom are 3, then the emission transitions between these states will be
(A) 3
(B) 4
(C) 5
(D) 6
Option d – 6
The condition for the emission of electrons in the photodiode is
(A) hv = Eg
(B) hv≤ Eg
(C) hv > Eg
(D) hv<Eg
Option c – hv > Eg
Calculate the number of alpha particles scattered per minute at 90° if the number of alpha particles scattered per minute at 60° is 100.
(A) 55
(B) 25
(C) 35
(D) 45
Option b – 25
Mean life period and half-life period of a radioactive element is
(A) inversely proportional to each other
(B) directly proportional to each other
(C) equal to each other
(D) not related to each other
Option b – directly proportional to each other
In the P-N junction, avalanche current flows in the circuit when biasing is ………
(A) forward
(B) reverse
(C) zero
(D) excess
Option b – reverse
If the mass of the electron is reduced to one-fourth, the Rydberg constant would ……..
(A) remain unchanged
(B) become double
(C) become half
(D) become one-fourth
Option d – become one-fourth
If the operation of a nuclear reactor is said to be critical, then the multiplication factor (K) has a value.
(A) 2
(B) 2.5
(C) 1.5
(D) 1
Option d – 1
In an NPN transistor, the collector current is 11 mA and the base current is 100 µA. Then the emitter current is
(A) 10.9 mA
(B) 10.1 mA
(C) 11.9 mA
(D) 11.1 mA
Option d – 11.1 mA
What is the binding energy per nucleon of the helium nucleus?
(A) Zero
(B) 8.8 MeV
(C) More than 8.8 MeV
(D) Less than 8.8 MeV
Option d – Less than 8.8 MeV
What percentage of original radioactive atoms is left after three half-lives?
(A) 20%
(B) 9.5%
(C) 5%
(D) 12.5%
Option d – 12.5%
Two samples of radioactive substances initially contain an equal number of atoms. Their half-life times respectively 5 years and 10 years. are the ratio of their disintegration rates after 20 years is
(A) 1 : 4
(B) 1 : 2
(C) 3 : 4
(D) 2 : 3
Option b – 1 : 2
In a full-wave rectifier circuit operating from mains with the frequency of 60 Hz, the fundamental frequency in the ripple would be
(A) 120 Hz
(B) 30 Hz
(C) 70.7 Hz
(D) 90 Hz
Option a – 120 Hz
When a semiconductor is heated, its conductance ………
(A) decreases
(B) increases
(C) remains the same
(D) may increase or decrease depending on the semiconductor
Option b – increases
The half-life of radioactive material is 4 h. If the initial amount is 300 g, then calculate the remaining amount after 24 h.
(A) 9.375 g
(B) 46.8 g
(C) 93.75 g
(D) 4.69 g
Option d – 4.69 g
The average life of a radioactive sample is
(A) twice its disintegration constant.
(B) half of its disintegration constant.
(C) equals to its disintegration constant.
(D) reciprocal of its disintegration constant.
Option d – reciprocal of its disintegration constant.
A change in temperature
(A) increases reverse resistance.
(B) affects V-I characteristics of the p-n junction.
(C) does not affect the characteristics of the p-n junction.
(D) increases forward resistance.
Option b – affects V-I characteristics of the p-n junction.
In Bohr’s model of the hydrogen atom, let T.E. represent total energy and P.E. represents potential energy. In going to a higher level
(A) T.E. decreases, P.E. increases.
(B) T.E. increases, P.E. increases.
(C) T.E. decreases, P.E. decreases.
(D) T.E. increases, P.E. decreases.
Option b – T.E. increases, P.E. increases.
If the defect for the nucleus of helium mass is 0.0303 then the binding energy amu, per nucleon for helium in MeV is
(A) 28
(B) 7
(C) 4
(D) 1
Option b – 7
In a sample of radioactive material, what fraction of the initial number of active nuclei will disintegrate after four half-lives of the sample?
(A) 0.75
(B) 0.50
(C) 0.94
(D) 0.25
Option c – 0.94
The input signal given to a CE amplifier having a voltage gain of 160 is V₁ = 2 cos (20t + 15°). The corresponding output signal is
(A) 320 cos (20t + 165°)
(B) 320 cos (20t + 195°)
(C) 160 cos (20t + 195°)
(D) 160 cos (20t+165°)
Option b – 320 cos (20t + 195°)
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