Nageen Prakashan Physics Class 12

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Nageen Prakashan Physics Class 12. We covered all the Nageen Prakashan Physics Class 12 in this post for free so that you can practice well for the exam.

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Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

The length of the simple pendulum increased by 4 times then its period increased by :

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

In which case does the potential energy decrease? :

Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

(A) the Total energy of the pendulum

(B) K.E. of the pendulum

(D) Zero

Option d - Zero

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

(A) Increases

(B) Decreases

(D) Is zero

Option c - Does not change

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

(A) 11%

(B) 20%

(D) 30%

Option b - 20%

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

(A) 8 s

(B) 4 s

(D) 2 s

Option c - 3 s

The length of the simple pendulum increased by 4 times then its period increased by :

(A) Two times

(B) Three times

(D) 1½ times

Option a - Two times

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

(A) 3927 s

(B) 2927 s

(D) 864 s

Option d - 864 s

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

(A) Straight line passing through the origin

(B) Ellipse

(D) Parabola

Option d - Parabola

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

(A) The length of the pendulum is small

(B) The mass of the pendulum is small

(D) The acceleration due to gravity is small

Option c - The amplitude of the oscillation is small

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

(A) 4 s

(B) 2 S

(D) 3 s

Option b - 2 S

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

(A) KE remains constant

(B) PE remains constant

(D) KE+PE is constant

Option d - KE+PE is constant

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

(A) 1/8

(B) 1/2

(D) 3/4

Option d - 3/4

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

(A) 1000 N/m

(B) 2000 N/m

(D) 3000 N/m

Option b - 2000 N/m

In which case does the potential energy decrease? :

(A) on compressing a spring

(B) on stretching a spring

(D) on the rising of an air bubble in water

Option d - on the rising of an air bubble in water

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Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

The length of the simple pendulum increased by 4 times then its period increased by :

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

In which case does the potential energy decrease? :

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