Nageen Prakashan Physics Class 12

Nageen Prakashan Physics Class 12. We covered all the Nageen Prakashan Physics Class 12 in this post for free so that you can practice well for the exam.

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Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

The length of the simple pendulum increased by 4 times then its period increased by :

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

In which case does the potential energy decrease? :

Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

(A) the Total energy of the pendulum

(B) K.E. of the pendulum

(D) Zero

Option d - Zero

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

(A) Increases

(B) Decreases

(D) Is zero

Option c - Does not change

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

(A) 11%

(B) 20%

(D) 30%

Option b - 20%

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

(A) 8 s

(B) 4 s

(D) 2 s

Option c - 3 s

The length of the simple pendulum increased by 4 times then its period increased by :

(A) Two times

(B) Three times

(D) 1½ times

Option a - Two times

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

(A) 3927 s

(B) 2927 s

(D) 864 s

Option d - 864 s

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

(A) Straight line passing through the origin

(B) Ellipse

(D) Parabola

Option d - Parabola

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

(A) The length of the pendulum is small

(B) The mass of the pendulum is small

(D) The acceleration due to gravity is small

Option c - The amplitude of the oscillation is small

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

(A) 4 s

(B) 2 S

(D) 3 s

Option b - 2 S

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

(A) KE remains constant

(B) PE remains constant

(D) KE+PE is constant

Option d - KE+PE is constant

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

(A) 1/8

(B) 1/2

(D) 3/4

Option d - 3/4

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

(A) 1000 N/m

(B) 2000 N/m

(D) 3000 N/m

Option b - 2000 N/m

In which case does the potential energy decrease? :

(A) on compressing a spring

(B) on stretching a spring

(D) on the rising of an air bubble in water

Option d - on the rising of an air bubble in water

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Physics Class 12 QnA Mock Test for Students

The work done by the string of a simple pendulum during one complete oscillation is equal to

The steel bob of a simple pendulum is replaced by a wooden bob of the same volume. Then its time period :

The length of a simple pendulum is increased by 44% the percentage increase in the time period is :

A ring is suspended from a point on its periphery by a 2.25 m long string. The period of oscillation :

The length of the simple pendulum increased by 4 times then its period increased by :

If the length of the second pendulum is increased by 2 %. How many seconds it will lose per day?

A graph is plotted between the length of the simple pendulum and the period, the nature of the graph is :

To show that a simple pendulum executes a simple harmonic motion, it is necessary to assume that :

A simple pendulum has a spherical empty bob of mass 50 g. Its period is 2 s. Now the bob is replaced by another solid bob of the same radius but a mass of 100 g. The new time period will be :

In a simple harmonic motion, the kinetic energy (KE) and the potential energy (PE) are such that throughout the motion :

What energy of the total energy is kinetic energy when the displacement is one-half of the amplitude? :

A 0.5 kg stone is dropped on a vertical spring from a height of 2 m. If the maximum compression of the spring is 10 cm, its force constant is :

In which case does the potential energy decrease? :

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