Namma Kalvi 12th Chemistry

Namma Kalvi 12th Chemistry. We covered all the Namma Kalvi 12th Chemistry MCQs in this post for free so that you can practice well for the exam.

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    Namma Kalvi 12th Chemistry Objective for Students

    Diethyl ketone sodium bisulphite reacts with dilute acid or base to give:

    (A) Pentanal

    (B) Pentanone

    (C) Butanal

    (D) Butanone

    Option b – Pentanone

    The most acidic hydrogen atom in alkanals is located at the:

    (A) Delta position

    (B) Gamma position

    (C) Alpha position

    (D) Beta position

    Option c – Alpha position

    The detection of the oxo group in an organic compound can be done using:

    (A) Tetracarbonyl nickel

    (B) Sodium nitropruside

    (C) Sodium dicyano aurate

    (D) Lithium hydrido aluminate

    Option b – Sodium nitropruside

    The anion of propanone obtained by alkali reacts with nitropruside ion to give a red-colored complex, indicating the presence of:

    (A) Ester group

    (B) Formyl group

    (C) Ether group

    (D) Oxo group

    Option d – Oxo group

    The anion of a ketone formed by alkali reacts with nitropruside ion to give a:

    (A) Black-colored complex

    (B) Violet-colored complex

    (C) Red-colored complex

    (D) Blue-colored complex

    Option c – Red-colored complex

    The least reactive compound towards hydrogen cyanide is:

    (A) Ethyl methyl ketone

    (B) Dimethyl ketone

    (C) Ethanal

    (D) Methanal

    Option a – Ethyl methyl ketone

    Mendelonitrile is prepared from:

    (A) Ethanal and hydrazine

    (B) Ethanal and formonitrile

    (C) Propanone and ammonia

    (D) Benzene carbaldehyde and formonitrile

    Option d – Benzene carbaldehyde and formonitrile

    Cyanohydrin formation is a “step-up” reaction as a new:

    (A) Carbon-Nitrogen single bond is formed.

    (B) Carbon-Oxygen single bond is formed.

    (C) Carbon-Carbon single bond is formed.

    (D) Carbon-Sulphur single bond is formed.

    Option c – Carbon-Carbon single bond is formed

    Propanone reacts with formonitrile to give:

    (A) Dimethyl ketone cyanohydrin

    (B) Ethanal cyanohydrin

    (C) Propanal cyanohydrin

    (D) Propane nitrile

    Option a – Dimethyl ketone cyanohydrin

    During the reaction between ethanal and ammonical silver nitrate, the oxidation state of silver changes from:

    (A) +3 to zero

    (B) +2 to +3

    (C) +1 to zero

    (D) +1 to +2

    Option c – +1 to zero

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