Organic Compounds Containing Nitrogen MCQ. We covered all the Organic Compounds Containing Nitrogen MCQ in this post for free so that you can practice well for the exam.
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MCQ on Organic Compounds Containing Nitrogen for NEET Students
……… will NOT undergo azo coupling reaction with benzene diazonium chloride.
(A) Aniline
(B) Phenol
(C) Anisole
(D) Nitrobenzene
Option d – Nitrobenzene
t-Butyl bromide on reaction with alcoholic ammonia undergoes ………. reaction.
(A) nucleophilic substitution
(B) elimination
(C) addition
(D) electrophilic substitution
Option b – elimination
A primary amine that can be obtained both by the reduction of cyanides and amides is ……….
(A) methylamine
(B) benzylamine
(C) aniline
(D) isopropylamine
Option b – benzylamine
N, N-Dimethylmethanamine is an isomer of ………
(A) ethylamine
(B) ethyldimethylamine
(C) ethylmethylamine
(D) n-butylamine
Option c – ethylmethylamine
Which of the following pair can be distinguished by the isocyanide test?
(A) Ethylamine and aniline
(B) Benzylamine and dimethylamine
(C) Diethylamine and trimethylamine
(D) Cyclohexylamine and aniline
Option b – Benzylamine and dimethylamine
Acetaldoxime reacts with sodium and ethanol to give water and compound (P), which gives compound (D), water, and nitrogen in reaction with nitrous acid in cold conditions. Compound (D) when heated with 95% H₂SO, at 443 K forms compound (S). Identify compounds (D) and (S) respectively.
(A) Ethanol, Ethene
(B) Ethylamine, Ethene
(C) Ethanol, Ethane
(D) Propan-2-ol, Propene
Option a – Ethanol, Ethene
How many of the following amines will undergo diazotization? tert-Butylamine, ethanamine, aniline, N-methylaniline, p-toluidine, m-chloroaniline, 2-phenylethanamine, 2,4,6-tribromoaniline.
(A) 4
(B) 5
(C) 6
(D) 8
Option a – 4
Nitrobenzene on reaction with tin and concentrated HCl forms ………..
(A) benzene
(B) toluene
(C) chlorobenzene
(D) aniline
Option d – aniline
Which of the following is more basic than aniline?
(A) N.N-Diphenylaniline
(B) N-Phenylaniline
(C) p-Nitroaniline
(D) Phenylmethanamine
Option d – Phenylmethanamine
Butan-l-amine (I). N-ethylethanamine-(II) and N,N-dimethylethanamine-(III) have the same molecular mass. The increasing order of their boiling points is :
(A) III <II<I
(B) I<II<III
(C) II<III<I
(D) II<I<III
Option a – III
The strongest base in aqueous solution among the following amines is :
(A) N, N-diethylethanamine
(B) N-ethylethanamine
(C) N-methylmethanamine
(D) ethanamine
Option b – N-ethylethanamine
Positive carbylamine test is shown by ………..
(A) N,N-dimethylbenzenamine
(B) N,N-diethylethanamine
(C) N-methylbenzenamine
(D) phenylmethanamine
Option d – phenylmethanamine
Ethylamine reacts with acetyl chloride in presence of pyridine to form ……….
(A) N-ethylethanamide
(B) N, N-diethylethanamide
(C) N-methylethanamide
(D) N-ethylpropanamide
Option a – N-ethylethanamide
Which of the following compounds will dissolve in an alkali solution after it undergoes a reaction with Hinsberg’s reagent?
(A) CH3NH₂
(B) (CH3)3N
(C) (C₂H5)2NH
(D) C6H5NHC6H5
Option a – CH3NH₂
The CORRECT sequence of reactions to convert p-nitrophenol into quinol involves :
(A) reduction, diazotization, and acidic hydrolysis
(B) acidic hydrolysis, diazotization, and reduction
(C) acidic hydrolysis, reduction, and diazotization
(D) diazotization, reduction, and acidic hydrolysis
Option a – reduction, diazotization, and acidic hydrolysis
Aniline is reacted with bromine water at room temperature and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute HCl. The compound so formed is converted into diazonium tetrafluoroborate, which is subsequently heated to get the final product ……..
(A) 1-bromo-4-fluorobenzene
(B) 4-bromoaniline
(C) 1,3,5-tribromo-2-fluorobenzene
(D) 1,3,5-tribromobenzene
Option c – 1,3,5-tribromo-2-fluorobenzene
What is the color of the dye produced after the reaction of benzene diazonium chloride with phenol in presence of an alkali?
(A) Red
(B) Yellow
(C) Orange
(D) Green
Option c – Orange
Test tube ‘X’ contains N-methylaniline. It is treated with Hinsberg reagent and excess KOH. The CORRECT observation is ……….
(A) the clear solution is obtained which on acidification gives insoluble compound
(B) insoluble material is obtained which gives a clear solution for acidification
(C) the insoluble compound is obtained which does not dissolve in acid
(D) the clear solution is obtained which on acidification remains as it is
Option c – the insoluble compound is obtained which does not dissolve in acid
Which of the following amide on Hoffmann bromamide reaction forms propanamine?
(A) Propanamide
(B) Pentanamide
(C) Ethanamide
(D) Butanamide
Option d – Butanamide
Which of the following statements is CORRECT in the case of Hoffmann bromamide degradation?
(A) It gives unsymmetrical amines.
(B) It gives tertiary amine
(C) It gives primary amine
(D) It does not give aromatic amines.
Option c – It gives primary amine
Which of the following CANNOT form intermolecular hydrogen bonds?
(A) Propan-2-amine
(B) Triethylamine
(C) Diphenylamine
(D) o-Toluidine
Option b – Triethylamine
Which of the following is CORRECT about the acylation of amines?
(A) It involves the replacement of the H-atom attached to nitrogen in amines by the alkyl group.
(B) It is an electrophilic substitution reaction.
(C) It is carried out in presence of a strong base like pyridine.
(D) Secondary amines do not undergo acylation.
Option c – It is carried out in presence of a strong base like pyridine.
Gabriel phthalimide synthesis is useful in the preparation of ………. amines.
(A) aromatic primary
(B) aliphatic primary
(C) aliphatic secondary
(D) aromatic secondary
Option b – aliphatic primary
Which of the following compounds is the weakest Brönsted base?
(A) Aniline
(B) Cyclohexylamine
(C) Phenol
(D) Cyclohexanol
Option c – Phenol
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